Calculate the amount of liquid in a partially filled horizontal cylinder tank with elliptical heads. This calculator uses feet for measurements.
one US gallon of water = 8.34 pounds. one US gallon of diesel fuel = 7.1 pounds one US gallon of gas = 6 pounds
Include the length of the two flanges in the cylinder length. It is assumed that cap depth h is equal to one quarter of the cylinders diameter.
V=(r²cos-¹((r-d)/R)-(r-d)Square root = √Dd-d² ))L where V is the patial volume of the cylinder r half the tanks height d the depth of the liquid inside the tank D the height of the tank L the lenght of the cylinder part thjat includes the flanges of the heads Vc = 𝝅D⊃3/24; where Vc is the volume of the elliptical head D the height of the tank
one cubic foot (ft³) = 1728 cubic inches (in³) one cubic foot (ft³) = 28316846.592 cubic millimetres (mm³) one cubic foot (ft³) = 0.028316846592 cubic metres (m³) one cubic foot (ft³) = 7.48051948051947 gallons (gal) US one cubic foot (ft³) = 6.22883545904283 gallons (gal) Imperial one square foot (ft²) = 144 square inches (in²) one square foot (ft²) = 92903.04 square millimetres (mm²) one square foot (ft²) = 0.09290304 square metres (m²)