Partial Volume in a Horizontal Cylinder Tank with Elliptical Heads

Calculate the amount of liquid in a partially filled horizontal cylinder tank with elliptical heads. This calculator uses inches for measurements.

The length of the two flanges (f) are part of the cylinder length, and it is assumed that the height of the cap (h) is equal to one quarter of the tanks diameter.

Approximate weight of Fuel or Water

one US gallon of water = 8.34 pounds.
one US gallon of diesel fuel = 7.1 pounds
one US gallon of gas = 6 pounds

Calculator

1. enter the diameter of the horizontal cylinder in inches
2. the length of the tank in inches (includes the flanges)
3. the depth of the liquid inside the tank in inches
4. the weight of the liquid in pounds per US gallon

Results

1. the cap height (h) inches
2. the volume of the horizontal cylinder tank in cubic inches
3. the volume of the tank in cubic feet
4. the volume of the tank in cubic metres
5. the total amount of liquid the tank can hold in US gallons
6. the amount of liquid inside the tank in US gallons
7. the amount of liquid inside the tank in Imperial gallons
8. the amount of liquid inside the tank in litres
9. the amount of liquid inside the tank in cubic feet
10. the weight of the liquid inside the tank based on lbs/gal US
11. the amount of liquid it will take to fill this tank in US gallons

Formula

V=(r²cos-¹((r-d)/R)-(r-d)Square root = √Dd-d² ))L
where V is the patial volume of the cylinder
r half the tanks height
d the depth of the liquid inside the tank
D the height of the tank
L the lenght of the cylinder part thjat includes the flanges of the heads

Vc = 𝝅D⊃3/24;
where Vc is the volume of the elliptical head
D the height of the tank

Conversions

one cubic inch (in³) = 0.000578703703703704 cubic feet (ft³)
one cubic inch (in³) = 0.000016387064 cubic metres (m³)
one cubic inch (in³) = 0.00432900432900432 gallons (gal) US
one cubic inch (in³) = 0.00360465014990905 gallons (gal) Imperial
one cubic inch (in³) = 0.016387064 litres (L)