The towns of A and B are 467.8 miles apart separated by one road. A and B leave at the same time with A traveling at an average speed of 55.6 miles per hour and B traveling at an average speed of 72.2 miles per hour. How long will it take before the meet and what is the distance they cover?

Two parties A and B are traveling towards each other at different speeds. How long will it take before they meet and how distance will each have covered?

Formula;

T = D ÷ Asp + Bsp

where T = time of travel - D = distance apart - Asp = average speed of A - Bsp = average speed of B then

Asp * T = distance covered by A
Bsp * T = distance covered by B

Solution:

72.2 + 55.6 = 127. 8
467.8 ÷ 127. 8 = 3.66 hours
converting 0.66 hours to minutes - there are 60 minutes in an hour 60 ÷ 100 = 0.6
0.66 * 0.6 = 0.396 rounded to two digits = 0.40 minutes
time of travel 3 hours and 40 minutes
55.6 * 3.66 = 203.496? A covers a distance of 203.496 miles
72.2 * 3.66 = 264.252? B covers a distance of 264.252 miles 

They will meet each other after 3 hours and 40 minutes of travelling at a distance of 203.496 miles from town A.

Calculation

1. distance from town A to town B in miles
2. average speed of A in miles per hour
3. average speed of B in miles per hour

Results

1. the time it takes for them to meet
2. distance travelled by A
3. distance travelled by B